用C语言中的for循环实现斐波那契数列

void fib(int);
int main(int argc, const char *argv[])
{
	int n;
	printf("请输入想查询的斐波那契数列的项数：");
	scanf("%d",&n);
	fib(n);
	printf("\n");
	return 0;
}

void fib(int n)
{
	int i;
	int fib1=1;
	int fib2=1;
	int fib;
	printf("斐波那契数列的前%d项为：\n",n);
	for(i=1;i<=n;i++)
	{
		if(i==1 || i==2)
		{
			printf("1\t");
		}
		else
		{
			fib = fib1 + fib2; 
			fib1 = fib2;
			fib2 = fib;
			printf("%d\t",fib);
		}
	}
}