代码如下,显示错误
   C4996    'strcpy': This function or variable may be unsafe. Consider using strcpy_s instead. To disable deprecation, use _CRT_SECURE_NO_WARNINGS. See online help for details.  

#include<iostream>
#include<string.h>
using namespace std;
char *getname(void);//function prototype
int main()
{
	char *name;
	name = getname();
	cout << name << "at" << (int *)name << "\n";
	delete[] name;//why use delete?
	name = getname();
	cout << name << "  at  " << (int *)name << "\n";
	system("pause");
	delete[] name;//why use delete? because return pn
	return 0;
}
char *getname()
{
	char temp[80];//temporary storage
	cout << "enter last name" << endl;
	cin >> temp;
	char *pn = new char[strlen(temp) + 1];
	strcpy(pn, temp);
	return pn;

}

解决方案:

项目->项目属性->C/C++ ->预处理器-》预处理器定义 下编辑中添加下面即可

_CRT_SECURE_NO_WARNINGS

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c++ 字符串 操作 'strcpy': This function or variable may be unsafe. Consider