一种在矩阵中交换F＃中行的简单方法(A simple way to swap rows in a matrix for F#)

一种在矩阵中交换F＃中行的简单方法(A simple way to swap rows in a matrix for F#)

有一种简单的方法可以在F＃中交换Matrix的行吗？

Is there a simple way to swap the rows of a Matrix in F#?

最满意答案

您可以使用切片语法来处理矩阵的整个行/列：

// Create sample matrix let m = Matrix.init 10 10 (fun x y -> float(x * 10 + y)) // Overwrite first row with the second row m.[0..0, 0..9] <- m.[1..1, 0..9]

切片语法允许您选择矩阵的一部分 - 在这种情况下，我们选择高度为1的矩阵，但您可以更普遍地使用该功能（该部分不必是单个列/行）。 我不认为有任何现有的交换两行的功能，但你可以使用切片并实现它如下：

let swap (m:matrix) a b = let tmp = m.[a..a, 1..9] m.[a..a, 1..9] <- m.[b..b, 1..9] m.[b..b, 1..9] <- tmp

You can use slicing syntax to manipulate with entire rows/columns of a matrix:

// Create sample matrix let m = Matrix.init 10 10 (fun x y -> float(x * 10 + y)) // Overwrite first row with the second row m.[0..0, 0..9] <- m.[1..1, 0..9]

The slicing syntax allows you to select a part of the matrix - in this case, we're selecting a matrix with the height 1, but you can use the feature more generally (the part doesn't have to be a single column/row). I don't think there is any existing function for swapping two rows, but you can use slices and implement it like this:

let swap (m:matrix) a b = let tmp = m.[a..a, 1..9] m.[a..a, 1..9] <- m.[b..b, 1..9] m.[b..b, 1..9] <- tmp